Vedic Maths

Vedic Division & Square Roots — Paravartya, Dhvajanka & Vilokanam

Vedic division techniques (Paravartya Yojayet, Dhvajanka, Ekadhikena) reduce long division to a single line of running sums. Square-root techniques (Vilokanam, Vargamula) find roots of perfect squares in seconds and approximate roots of non-perfect squares to 1–2 decimal places mentally.

Exam relevance: Direct division questions: 1–3 per Quant paper. Indirect (averages, ratios, time-and-work, simple/compound interest): 8–12 questions per paper depend on fast division.

In-Depth Tutorial

A formal, accessible 800–1000 word walkthrough of this topic, written for the serious aspirant. Switch to हिन्दी using the toggle on the right.

Why Division Deserves a Chapter of Its Own

Division is the slowest of the four basic arithmetic operations and consequently the most expensive in time when performed by the conventional long-division method. A three-digit number divided by a two-digit number using long division typically takes thirty to forty seconds; a four-digit dividend can take a full minute. In Banking Prelims and Staff Selection Commission Tier-I papers, between four and seven questions per paper require at least one division of this size — most commonly in percentage, ratio, time-and-work and average problems. Compressing this calculation through Vedic methods saves between two and four minutes per paper.

Vedic division rests on two principal techniques: Paravartya Yojayet for divisors that are slightly more than a base, and a running-sum technique for division by nine. Square roots are addressed through Vilokanam for perfect squares and the Dvanda Yoga method for general numbers. The same chapter also covers the inverse percentage and ratio shortcuts that grow naturally from division.

Division by Nine — The Running Sum Method

Division of any number by nine, regardless of length, can be performed in a single horizontal line using a running-sum technique. The candidate writes the dividend along the top line. The first quotient digit is the first digit of the dividend. Each subsequent quotient digit is the running sum of the dividend digits encountered so far, modulo nine. The remainder is the running sum of all dividend digits, modulo nine.

Consider 234 ÷ 9. The first quotient digit is 2. The next is 2 + 3 = 5. The remainder portion accumulates as 2 + 3 + 4 = 9, which becomes 0 with a carry of 1 to the previous quotient digit. The final answer is quotient 26, remainder 0. Consider 1234 ÷ 9: 1, 1+2=3, 1+2+3=6, remainder 1+2+3+4 = 10 → remainder 1, carry 1. Quotient 137, remainder 1. With ten practice problems this technique becomes automatic, and any division by nine — whatever the size of the dividend — is solved in under fifteen seconds.

Paravartya Yojayet — Division Near a Base

Paravartya Yojayet, meaning 'transpose and apply,' addresses divisions in which the divisor is slightly more than a base of ten, hundred or thousand. For a divisor such as 12, the procedure is to transpose the deficiency-related digits — that is, to invert the sign of the digits beyond the leading one — and to apply repeated addition to the dividend. The technique converts division into a sequence of small additions, which the candidate can perform mentally.

Consider 1234 ÷ 12. The divisor 12 is at base 10 with surplus 2; the transposed value is −2. The candidate writes the dividend in pairs of digits and applies the transposition iteratively, producing the quotient and remainder in a single horizontal pass. The full procedure requires five solved examples for full clarity, after which any division by a divisor between ten and twenty can be performed in twelve to fifteen seconds. The same logic extends to divisors near hundred, where the technique replaces a half-minute long division with a ten-second paper-and-pen calculation.

Vilokanam — Square Roots of Perfect Squares

Vilokanam, meaning 'by inspection,' produces the square root of a perfect square by simple observation. The candidate first determines the number of digits in the root, which equals the number of pairs in the original number when the digits are grouped from the right. The first digit of the root is the integer part of the square root of the leftmost group. The last digit of the root is determined by the unit digit of the original number, using the table of last-digit correspondences: 1 ↔ 1 or 9, 4 ↔ 2 or 8, 5 ↔ 5, 6 ↔ 4 or 6, 9 ↔ 3 or 7, 0 ↔ 0.

Consider √2025. There are two pairs (20, 25), so the root has two digits. The first digit is the integer square root of 20, which is 4 (since 4² = 16 ≤ 20 < 25 = 5²). The unit digit of 2025 is 5, so the last digit of the root is 5. The root is 45. To resolve the ambiguity when the unit digit corresponds to two possible last digits, multiply the leading group by the next integer; if the product is less than the leading group, take the larger candidate, otherwise the smaller. With twenty practice roots the candidate can identify any four-digit perfect square root in under ten seconds.

Dvanda Yoga — Square Roots of General Numbers

When the number is not a perfect square or when the question asks for an approximate root, the Dvanda Yoga method delivers the answer column by column. The candidate begins by grouping the digits from the right in pairs, identifying the first quotient digit by inspection of the leftmost group, and then computing each subsequent quotient digit using a duplex-style adjustment that incorporates the carry from the preceding step.

The full Dvanda Yoga procedure is most efficiently learned through five worked examples — one each for two-digit, three-digit, four-digit, five-digit and decimal results. Once the pattern is recognised, the candidate can extract any square root to two decimal places in under thirty seconds. For competitive examinations, however, the perfect-square case via Vilokanam is the more frequently used technique, and Dvanda Yoga serves chiefly for the data-interpretation block and for problems involving standard deviation.

A Five-Day Plan for Division and Roots

An efficient plan covers division and roots in five days. Day one introduces division by nine through the running-sum technique with twenty problems of increasing dividend length. Day two introduces Paravartya Yojayet for divisors near ten with twenty problems. Day three extends Paravartya to divisors near hundred. Day four covers Vilokanam square roots with twenty perfect squares from three to six digits. Day five is mixed practice with twenty division and ten square-root problems under timed conditions of fifteen seconds per problem.

By the end of the fifth day, the candidate can divide by nine, by any divisor near ten or hundred, and can extract perfect square roots up to six digits — all within strict examination time budgets. The combined time saving across one paper is between three and five minutes, sufficient for three to four additional confident attempts.

1Division by 9 (Ekadhikena Method)

Division of any number by 9 is solved by a running sum of digits; the running sum gives the quotient and the final digit-sum gives the remainder.

Procedure: the first digit of the dividend = first digit of the quotient. Each subsequent digit of the quotient is the running sum of the dividend's digits up to that point. The remainder = sum of all digits of the dividend (with adjustments if it exceeds 9).

Examples
  • 234 ÷ 9: q1 = 2; q2 = 2 + 3 = 5; running sum = 2 + 3 + 4 = 9 → quotient = 25, remainder = 9 → adjust: 25 → 26 with remainder 0.
  • 1234 ÷ 9: 1; 1+2 = 3; 1+2+3 = 6; remainder = 1+2+3+4 = 10 → carry → quotient = 137, remainder = 1.
  • 456 ÷ 9: 4; 4+5 = 9; remainder = 4+5+6 = 15 → quotient 50, remainder 6.
  • 12321 ÷ 9: 1; 1+2 = 3; 3+3 = 6; 6+2 = 8; remainder = 8+1 = 9 → quotient 1369, rem 0.
Exam tip: If at any point a digit-sum exceeds 9, carry the tens digit to the next column. Always validate the remainder by 9-test (digit-sum mod 9).

2Paravartya Yojayet — Division by Numbers Near a Power of 10

Paravartya Yojayet means 'transpose and apply'. It is used to divide a number by a divisor that is close to a power of 10 (e.g. 88, 89, 91, 99, 999).

Step 1: write the divisor as base ± d. Step 2: transpose the digits of d (with sign change). Step 3: bring down the first digit of the dividend; multiply by the transposed d; add to next dividend digit; repeat. The last column gives the remainder.

Examples
  • 1234 ÷ 99 (d = 1, transpose = +1): bring 1; 1; 2 + 1 = 3; 3 + 3 = 6; remainder column: 1×4 + 4 = ... → quotient 12, remainder 46.
  • 12345 ÷ 89 (d = 11, transpose = +11): apply column-wise → quotient ≈ 138, rem 63.
  • Use only when the divisor's deficit/excess from a base is small (≤ 15).
  • 456 ÷ 91 → quotient 5, remainder 1 (verify: 5 × 91 = 455, 456 − 455 = 1).
Exam tip: Paravartya is most useful when the divisor's deviation from a power of 10 is a single digit. For divisors like 89 (d=11), the carries get messy — fallback to standard long division.

3Square Roots of Perfect Squares (Vilokanam)

Vilokanam means 'mere observation'. It finds the square root of a perfect square in seconds by inspecting the last digit and the leading digits.

Step 1: pair the digits of the perfect square from the right (one pair per digit of the root). Step 2: the LAST digit of the root is determined by the last digit of the square (0→0, 1→1or9, 4→2or8, 5→5, 6→4or6, 9→3or7). Step 3: the FIRST digit of the root is the largest n with n² ≤ leading pair. Step 4: choose between the two candidates by mid-test: if the square is < n(n+1)·100, use the smaller candidate; else the larger.

Examples
  • √1225: last digit 5 → root ends in 5. Leading pair 12 → n² ≤ 12 → n = 3. Root = 35. ✓ (35² = 1225)
  • √4624: last digit 4 → root ends in 2 or 8. Leading pair 46 → n = 6. 6×7 = 42 < 46 → use larger candidate → root ends in 8 → 68. ✓ (68² = 4624)
  • √7569: last digit 9 → root ends in 3 or 7. Leading pair 75 → n = 8. 8×9 = 72 < 75 → use larger → 87. ✓ (87² = 7569)
  • √9801: last digit 1 → root ends in 1 or 9. Leading pair 98 → n = 9. 9×10 = 90 < 98 → larger → 99. ✓
Exam tip: Vilokanam works ONLY for perfect squares. If the number is not a perfect square (last digit 2, 3, 7, or 8), STOP — Vedic does not apply directly.

4Approximate Square Roots (Dvanda Yoga)

For non-perfect squares, the Dvanda Yoga (duplex) method gives a square root accurate to 2–3 decimal places mentally.

Step 1: pair digits from the decimal point (or the right end if integer). Step 2: find the integer part of the root by inspection. Step 3: subtract the square of the integer part from the leading pair; bring down the next pair. Step 4: divide the running remainder by twice the current quotient — append that digit to the quotient and subtract its square (duplex). Repeat for each digit of precision.

Examples
  • √50 ≈ 7.07 (integer part 7, since 7²=49, remainder 1).
  • √10 ≈ 3.162 (integer 3, refine: 1.000/(6) = 0.166; subtract 0.027; next iteration → 3.16).
  • √200 ≈ 14.14 (integer 14, since 14²=196).
  • √110 ≈ 10.488 (integer 10).
Exam tip: The duplex method is precise but iteration-heavy. For exam speed, memorise √2 ≈ 1.414, √3 ≈ 1.732, √5 ≈ 2.236, √7 ≈ 2.645, √10 ≈ 3.162 — these cover most exam scenarios.

Vedic Short Tricks

Use these speed tricks in the exam. Each trick is followed by a worked example so you can verify the shortcut yourself.

Trick 1Division by 9 — running-sum method

First digit of quotient = first digit of dividend. Each next digit = running sum of dividend digits so far. Remainder = sum of all digits (mod 9).

Example: 234 ÷ 9 → 2, 5; remainder 9 → adjust → quotient 26, rem 0.
Trick 2Division by 5 / 25 / 50

÷ 5 = ×2 then ÷ 10. ÷ 25 = ×4 then ÷ 100. ÷ 50 = ×2 then ÷ 100. Skip long division entirely.

Example: 375 ÷ 25 = 375 × 4 / 100 = 1500 / 100 = 15.
Trick 3Square-root last-digit table

Memorise: square ends 0→root 0; 1→1 or 9; 4→2 or 8; 5→5; 6→4 or 6; 9→3 or 7. Squares NEVER end in 2, 3, 7 or 8.

Example: √4624: last digit 4 → root ends in 2 or 8.
Trick 4Square-root mid-test (n × (n+1))

When you have two candidate digits, test against n × (n+1) × 100. If the square < n(n+1)·100, pick the SMALLER candidate; else the LARGER.

Example: √4624: leading 46, n=6, 6×7=42 < 46 → pick 8 → 68.
Trick 5Memorise common irrational roots

√2=1.414; √3=1.732; √5=2.236; √7=2.645; √10=3.162; √11=3.316; √13=3.606. These appear in 60% of geometry / mensuration problems.

Example: Equilateral triangle of side 6 → area = (√3/4)×36 = 9 × 1.732 = 15.588.

Quick Revision Facts

  • Perfect squares NEVER end in 2, 3, 7 or 8.
  • Last digit of √x: 1↔1or9; 4↔2or8; 5↔5; 6↔4or6; 9↔3or7.
  • ÷ 5 = ×2 ÷ 10; ÷ 25 = ×4 ÷ 100.
  • 9-test: a number is divisible by 9 iff its digit-sum is divisible by 9.

Frequently Asked Questions

Last digit 6 → root ends in 4 or 6. Leading pair 29 → n=5 (5²=25). 5×6=30 > 29 → pick smaller candidate → 54. Verify: 54² = 2916. ✓

1700's last digit is 0, but the digit before (7) means it is NOT a perfect square. Vilokanam works only for perfect squares. Use Dvanda Yoga or fallback to standard root extraction (≈ 41.23).